www.ndwl.net > lim(n到无穷) n∫(0,π/4)[tAnx]^nDx

lim(n到无穷) n∫(0,π/4)[tAnx]^nDx

任何实数的平方,都是非负的,仅此而已。 只是为了推出:1+y*y >= 2y。

a[n]+a[n+2] = ∫{0,π/4} (tan(x))^n dx+∫{0,π/4} (tan(x))^(n+2) dx = ∫{0,π/4} (tan(x))^n·(1+tan²(x)) dx = ∫{0,π/4} (tan(x))^n·(1/cos²(x)) dx = ∫{0,π/4} (tan(x))^n·(tan(x))' dx = (tan(π/4))^(n+1)/(n+1)-(tan(0))^(n+1)/(n+1...

网站地图

All rights reserved Powered by www.ndwl.net

copyright ©right 2010-2021。
www.ndwl.net内容来自网络,如有侵犯请联系客服。zhit325@qq.com